Dear Reader, below you will find 3 easy types of classification problems. In these problems, you have to find the odd option among all the given options. These are very easy to score.
Type I: Classification Based on Alphabet Positions
In this type, you will be able to classify the terms based on the position of the alphabets. You have to pick the odd man out which does not follow the rules. Below example will help you understand this.
Example Question 1: Four of the five are alike on the basis of their position in English alphabet. Which is the one that does not belong to the group?
a) BDF b) HJL c) NPS d) RTV e) VXZ
Solution:
This is a simple question.
On seeing the logic used, you may find that the words are formed by incrementing every letter by 2 positions.
i.e., B + 2 = D and D + 2 = F.
If you are not able to understand the above logic (rule), here is your explanation. D is 2 positions the right of D and F is 2 positions to the right of D.
But option c) NPS does not follow the above rule.
Except option c) all the other options use the same logic.
Type II: Classification Based on Meanings/Context
This type is similar to type 1, but all the options will be meaningful words. You have to find the odd option based on the meaning or context.
Below is your example question.
Example Question 2: Four of the five are alike in a certain way and so form a group. Which is the one that does not belong to the group?
a) Chalk b) Duster c) Board d) Class-room e)Book
Solution:
The odd one is class-room.
All other options given are used in class room.
Type III: Classification of Numbers
In this type, you will be able to classify/group numbers based on some numeric logic. You have to identify the number that does not follow the rule. You will understand better after reading the below example.
Example Question 3: Four of the five are alike in a certain way and so form a group. Which is the one that does not belong to the group?
a) 25 b) 49 c) 81 d) 121 e) 196
Solution:
All the options are square of numbers 5, 7, 9, 11 and 14 respectively.
Here except 14, remaining are odd numbers. Hence option e) is odd one.
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